# What mass is associated with 9.04xx10^23 individual sodium atoms?

Well $\text{1 mole}$ of sodium is $6.022 \times {10}^{23}$ individual sodium atoms.
And $\text{1 mole}$ of sodium, $6.022 \times {10}^{23}$ individual sodium atoms has a mass of $22.99 \cdot g$.
So if we have $9.04 \times {10}^{23}$ sodium atoms we have by definition $\frac{3}{2} \text{ moles}$ of sodium. So we have a mass of $\frac{3}{2} \cdot m o l \times 22.99 \cdot g \cdot m o {l}^{-} 1$ $=$ ??g