# Question #a4edb

Aug 31, 2016

Let the buggies start towards each other simultaneously and collide after time $t$ sec.

Initial distance between the buggies$= 160 - 25 = 135 c m$
Distance travelled by Buggy A in this time interval$= 14.55 t c m$
Distance travelled by Buggy B in the same time interval$= 39.27 t c m$
Total distance travelled by both $=$ Initial distance.
$\therefore 14.55 t + 39.27 t = 135$
$\implies 53.54 t = 135$
Solving for $t$
$t \approx 2.5 s$
Distance moved by Buggy A in this time$= 14.55 t \approx 36.7 c m$

Along the meter stick the collision occurs at
$25 + 36.7 = 61.7 c m$ mark