Question #342b9
1 Answer
Jan 31, 2017
A matter of counting:
Explanation:
P(R,R,G):
1st draw: 8R in 40: P=8/40=1/5
2nd draw: 7R in 39: P=7/39
3rd draw: 11G in 38: P=11/38
Multiply these probabilities:
P(R,B,notY):
1st draw: 8R in 40: P=8/40=1/5
2nd draw: 12B in 39: P=12/39
3rd draw: (38-9=29)noY in 38: P=29/38
