Question

Question #81d8b

Answer 1

I may be wrong on this so check it....

Explanation:

I would think that this is the probability of two events that can happen simultaneously (be even, event `A`, or in group N, event `B`) :
I would say that the probability of this event `A or B` is:

`P(AuuB)=P(A)+P(B)-P(AnnB)`

Where the last intersection probability bit is included to avoid repetitions.

We have:
`75` possible event;
`37` possibilities to come out even;
`15` possibilities to be in group N;
`7` possibilities to be in group N and be even;

so:

`P(A)=37/75=0.493`
`P(B)=15/75=0.2`
`P(AnnB)=7/75=0.093`

So:

`P(AuuB)=0.493+0.2-0.093=0.6`

or: `60%`