Question #df1ef

1 Answer
Anjali G
Nov 23, 2016

P(1-3i)=-13-6iP(1−3i)=−13−6i

Explanation:

P(x)=x^2-5P(x)=x2−5

P(1-3i)=(1-3i)^2-5P(1−3i)=(1−3i)2−5
=(1-3sqrt(-1))(1-3sqrt(-1))-5=(1−3√−1)(1−3√−1)−5
=1-3sqrt(-1)-3sqrt(-1)+9(-1)-5=1−3√−1−3√−1+9(−1)−5
=1-6i-14=1−6i−14
=-13-6i=−13−6i

Related questions
See all questions in Complex Number Plane
Impact of this question
1190 views around the world
You can reuse this answer
Creative Commons License