# How is hydrogen formed from zinc and methane under basic conditions?

Oct 9, 2016

You form the zincate ion from zinc and hydroxide, and methane and water give the so-called steam reforming reaction.

#### Explanation:

Zinc is quite an active metal, and will be oxidized by EITHER ${H}_{3} {O}^{+}$ or $H {O}^{-}$. Dihydrogen is the reduction product.

$Z n \left(s\right) + 2 N a O H \left(a q\right) + 2 {H}_{2} O \left(l\right) \rightarrow 2 N {a}^{+} + Z n {\left(O H\right)}_{4}^{2 -} + {H}_{2} \left(g\right) \uparrow$

Methane gas and steam (+ energy) will give dihydrogen gas and carbon dioxide:

$C {H}_{4} \left(g\right) + 2 {H}_{2} O \left(l\right) + \text{energy } \rightarrow C {O}_{2} \left(g\right) + 4 {H}_{2} \left(g\right)$

Are these reactions balanced? They should be!