How do you solve #d-4 <= (13-d)/3# ?

1 Answer
Sep 13, 2016

Answer:

#d <= 25/4#

Explanation:

If I read it correctly - upside down - this is an inequality:

#d-4 <= (13-d)/3#

First multiply both sides by #3# to get:

#3d-12 <= 13 - d#

Add #d+12# to both sides to get:

#4d <= 25#

Divide both sides by #4# to get:

#d <= 25/4#

Any #d# satisfying the original inequality will satisfy this final one and since all of these operations are reversible, any #d# satisfying this final inequality will satisfy the original one.