Question

Question #88190

Answer 1

`13+(n-1)*(-5/3)`

Explanation:

I think this is an arithmetic progression. Therefore,
`T_n=a+(n-1)d`, where `a` = first term, `n` = number of term and `d`=common different.

`13+27*(-5/3) = 13+(28-1)*(-5/3)=T_28`

Therefore we can say that,
`a=13, d=(-5/3)`

so, `T_n = 13+(n-1)*(-5/3)`