# What is the mass of calcium iodide required for a 2*L volume of calcium iodide whose concentration is 2*mol*L^-1?

Feb 6, 2017

If you mean $\text{calcium iodide}$ then you need a mass of $587.78 \cdot g$.

#### Explanation:

$\text{Concentration"="Moles of solute"/"Volume of solution}$

And thus $\text{moles of solute"="concentration"xx"volume of solution}$

And from the boundary conditions of the problem:

$\text{moles of solute"="concentration"xx"volume}$

$\text{moles of solute} = 2.0 \cdot m o l \cdot {L}^{-} 1 \times 1 \cdot L = 2.0 \cdot m o l$.

And $\text{2 moles of calcium iodide}$ represents a mass of 2*"mol"xx293.89* g*mol^-1=??g.