For a litre volume, what is the mass of calcium chloride present in a #2*mM# solution of #CaCl_2#?

1 Answer
Sep 17, 2016

Answer:

A stoichiometric quantity, approx. #222# #mg#.

Explanation:

#"Molarity"# #=# #"Moles of solute"/"Volume of solution"#, and thus #"molarity"# has units of #mol*L^-1#. And thus,

#"Moles of solute"="Volume of solution"xx"molarity"#

We have a #2"mM"# solution, i.e. a #2.0xx10^-3mol*L^-1# of #CaCl_2#, and, clearly, there are #2.0xx10^-3mol# of #CaCl_2# present in solution.

Thus, with respect to #CaCl_2# there are ............

#1*cancelLxx2.0xx10^-3cancel(mol*L^-1)xx110.98*g*cancel(mol^-1)# #=# #0.222*g# calcium chloride. What is the concentration of this solution with respect to #Cl^-# ion?