# What two integers surround root(3)54?

$3 < \sqrt[3]{54} < 4$

#### Explanation:

There are two ways (at least that I can see) as to how to approach this question. We can try to work our way through the cube root of 54 and find the answer that way, or we can cube integers until we "surround" the number 54. I'll do it that second way.

${1}^{3} = 1$
${2}^{3} = 8$
${3}^{3} = 27$
${4}^{3} = 64$

And so $3 < \sqrt[3]{54} < 4$