# Question #0a23d

Sep 27, 2016

$x = \left(\sqrt[3]{\frac{4}{9}} , 1\right)$

#### Explanation:

Supposing that you need is

$3 {x}^{\frac{4}{3}} - 5 {x}^{\frac{2}{3}} + 2 = 0$ then making $y = {x}^{\frac{2}{3}}$ we have in the new coordinates

$3 {y}^{2} - 5 y + 2 = 0$ and solving for $y$ we have

$y = \frac{2}{3}$ and $y = 1$

so ${x}^{\frac{2}{3}} = \frac{2}{3}$ and $x = \sqrt[3]{\frac{4}{9}}$ and $x = 1$