Question #c4c4e

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Answer 1 · 2016-10-03T08:54:31

The empirical formula given should be $C_2H_4O$ .

Then let the molecular formula be $(C_2H_4O)n$ .

Considering atomic masses as

$C->12"g/mol"$

$O->16"g/mol"$

$H->1"g/mol"$

We can get calculated molar mass of the compound is $(2*12+4*1+16*1)n=44n" g/mol"$

Equating it with given molar mass we get

$44n=88.12$

$=>n=88.12/44~~2$

Hence the MF of the compound is

$C_4H_8O_2$