Question

Question #2f8c3

Answer 1

A

Explanation:

It is a case of Horizontally Launched Projectile

Let us calculate Time of flight `T`
It is the total time taken by the steel ball to fall through height `h` and cover distance `r`.

Using kinematic equation for free vertical fall under influence of gravity.
`y= u_yt + 1/2 g t^2`
For `y= h , t=T`, we get
`h= 0xxT + 1/2 g T^2`
`=>T= sqrt((2h)/g)`

Range `r` is the horizontal distance covered during the time of flight `T`.

Using kinematic equation
`x= u_xt`
When `t=T , x=r`. Therefore we get

`r=u_xT`
`r=uxxsqrt((2h)/g)`

`=>r^2=kh` .....(1)
where `k=2u^2 /g` and is a constant

Equation (1) is a quadratic passing through origin. As it is of the form `y^2=x`, hence option A.