Question #2f8c3

1 Answer
Jan 18, 2017

Answer:

A

Explanation:

It is a case of Horizontally Launched Projectile

Let us calculate Time of flight #T#
It is the total time taken by the steel ball to fall through height #h# and cover distance #r#.

Using kinematic equation for free vertical fall under influence of gravity.
#y= u_yt + 1/2 g t^2#
For #y= h , t=T#, we get
#h= 0xxT + 1/2 g T^2#
#=>T= sqrt((2h)/g)#

Range #r# is the horizontal distance covered during the time of flight #T#.

Using kinematic equation
# x= u_xt#
When #t=T , x=r#. Therefore we get

#r=u_xT#
#r=uxxsqrt((2h)/g)#

#=>r^2=kh# .....(1)
where #k=2u^2 /g# and is a constant

Equation (1) is a quadratic passing through origin. As it is of the form #y^2=x#, hence option A.