Question

What mole is occupied by `1*mol` of gas under standard conditions?

Answer 1

`V=22.4*dm^3`

Explanation:

`V=(nRT)/P`

`V=(1*cancel(mol)xx0.0821*L*cancel(atm)*cancel(K^-1)*cancel(mol^-1)xx273*cancelK)/(1*cancel(atm))`

`=22.4*L` or `22.4*dm^3`

Note that `1*dm^3=(1xx10^-1*m)^3=1xx10^-3m^3=1*L`, i.e. `1*L=1*dm^3=10^-3m^3`.