# What mole is occupied by 1*mol of gas under standard conditions?

Dec 27, 2016

$V = 22.4 \cdot {\mathrm{dm}}^{3}$

#### Explanation:

$V = \frac{n R T}{P}$

$V = \frac{1 \cdot \cancel{m o l} \times 0.0821 \cdot L \cdot \cancel{a t m} \cdot \cancel{{K}^{-} 1} \cdot \cancel{m o {l}^{-} 1} \times 273 \cdot \cancel{K}}{1 \cdot \cancel{a t m}}$

$= 22.4 \cdot L$ or $22.4 \cdot {\mathrm{dm}}^{3}$

Note that $1 \cdot {\mathrm{dm}}^{3} = {\left(1 \times {10}^{-} 1 \cdot m\right)}^{3} = 1 \times {10}^{-} 3 {m}^{3} = 1 \cdot L$, i.e. $1 \cdot L = 1 \cdot {\mathrm{dm}}^{3} = {10}^{-} 3 {m}^{3}$.