# What mass is associated with a 2*mol quantity of potassium dichromate?

Sep 20, 2017

Potassium dichromate has a molar mass of $294.18 \cdot g \cdot m o {l}^{-} 1$.

#### Explanation:

And we got a 2 mole quantity, so we take the product.....

$2 \cdot \cancel{m o l} \times 294.18 \cdot g \cdot \cancel{m o {l}^{-} 1} \cong 588 \cdot g$......

Sep 20, 2017

$592 g$

#### Explanation:

When you talk about gram atoms, I think you're speaking about Molar Mass, like gramspermole $\left(g m o {l}^{-} 1\right)$

Moles doesn't affect the value of Molar mass of a compound, hence it's just a term that wants to drive you far away from the answer..

$\text{Formula} = {K}_{2} C {r}_{2} {O}_{7}$ that's your equation right?

$C r = 52$

$K = 40$

$O = 16$

Hence...

$\text{Molar Mass} = {K}_{2} C {r}_{2} {O}_{7} g m o {l}^{-} 1$

$\text{Molar Mass} = \left(40 \times 2\right) + \left(52 \times 2\right) + \left(16 \times 7\right) g m o {l}^{-} 1$

$\text{Molar Mass} = \left(80 + 104 + 112\right) g m o {l}^{-} 1$

$\text{Molar Mass} = 296 g m o {l}^{-} 1$

Hence $2$ moles of it will give..

$\Rightarrow 2 m o l s \times 296 g m o {l}^{-} 1$

$\Rightarrow 2 \cancel{m o l s} \times 296 g \cancel{m o {l}^{-} 1}$

$\Rightarrow 2 \times 296 g$

$\Rightarrow 592 g$

Hope this helps!