Question #89a1e Calculus Differentiating Trigonometric Functions Derivative Rules for y=cos(x) and y=tan(x) 1 Answer Henry W. Oct 27, 2016 (dy)/(dx)=-6x^2sin(x^3)cos(x^3) Explanation: d/(dx)cos^2(x^3) We have to apply chain rule, where u=cos(x^3) (dy)/(du)=d/(du)u^2=2u=2cos(x^3) (du)/(dx)=d/(dx)cos(x^3)=-3x^2sin(x^3) (dy)/(dx)=(dy)/(du)*(du)/(dx)=2cos(x^3)*-3x^2sin(x^3) =-6x^2sin(x^3)cos(x^3) Answer link Related questions What is the derivative of y=cos(x) ? What is the derivative of y=tan(x) ? How do you find the 108th derivative of y=cos(x) ? How do you find the derivative of y=cos(x) from first principle? How do you find the derivative of y=cos(x^2) ? How do you find the derivative of y=e^x cos(x) ? How do you find the derivative of y=x^cos(x)? How do you find the second derivative of y=cos(x^2) ? How do you find the 50th derivative of y=cos(x) ? How do you find the derivative of y=cos(x^2) ? See all questions in Derivative Rules for y=cos(x) and y=tan(x) Impact of this question 2820 views around the world You can reuse this answer Creative Commons License