# Question #b903b

Oct 13, 2016

$- 2 {x}^{2} \left(- 5 {x}^{2} + 4 {x}^{3}\right) = - 8 {x}^{5} + 10 {x}^{4}$

#### Explanation:

To write the given polynomial in standard form, we distribute and then re-order the terms to be in descending order of degree.

$- 2 {x}^{2} \left(- 5 {x}^{2} + 4 {x}^{3}\right) = \left(- 2 {x}^{2}\right) \left(- 5 {x}^{2}\right) + \left(- 2 {x}^{2}\right) \left(4 {x}^{3}\right)$

$= 10 {x}^{4} - 8 {x}^{5}$

$= - 8 {x}^{5} + 10 {x}^{4}$