Question #0e278

1 Answer
Oct 13, 2016

Answer:

#3sqrt(2)-4sqrt(5)#

Explanation:

In this question, it was establish that #4sqrt(5)-3sqrt(2)# is a square root of #98-sqrt(10)#. To get the other square root, we can simply multiply by #-1#.

Notice that for any #x#, we have

#x^2 = 1x^2 = (-1)^2x^2 = (-x)^2#

meaning that if #x# is a square root of #x^2#, then so is #-x#. Applying that here, we get the other square root as

#-(4sqrt(5)-3sqrt(2)) = 3sqrt(2)-4sqrt(5)#