Question #a18d2

1 Answer
Oct 13, 2016

Answer:

#"speed : "19.30 " "m/s#

#"displacement : "59" "meters#

Explanation:

enter image source here

#"the slope of graph is equal to acceleration"#

#tan alpha=3.00=(v_f-4.30)/5#

#3*5=v_f-4.30#

#15=v_f-4.30#

#v_f=15+4.30#

#v_f=19.30" "m/s#

#"area under graph is equal to displacement "#

#delta x=(4.30+19.30)/2*5#

#Delta x=(23.60)/2*5#

#Delta x=59" "meters#

enter image source here

#"or..."#

#v_f=v_i+a*t#

#v_f:"final speed"#

#a:"acceleration"#

#t:"time elapsed"#

#v_f=4.30+3*5#

#v_f=4.30+15#

#v_f=19.30" "m/s#

#Delta x=v_i*t+1/2*a*t^2#

#Delta x=4.30*5+1/2*3*5^2#

#Delta x=21.5+37.5#

#Delta x=59" "meters#