# Question #8892a

Feb 25, 2017

The passenger's velocity is indeterminate from the information given (no direction).
The passenger's speed relative to the ground is $25.0 \frac{k m}{h}$

#### Explanation:

The train is moving at a speed relative to the ground $W = 30.0 \frac{k m}{h}$

The passenger is moving at a speed relative to the train $E = 5.0 \frac{k m}{h}$

To calculate the relative speed of the passenger to the ground, $P G S$ we would add his speed to the speed of the train relative to the ground.

$P G S = W + E$

But here the direction of travel for the passenger is opposite that of the train, so his speed becomes a negative value.

$P G S = W - E$

$P G S = 30.0 - 5.0 = 25.0 \frac{k m}{h}$

If the train were to be travelling north at this moment, the passenger would be travelling at a $v e l o c i t y 25.0 \frac{k m}{h}$ north relative to the ground.