Question

What mass of `"nickel(II) chloride hexahydrate"` is present in a `250*mL` volume of `1.00*mol*L^-1` concentration?

Answer 1

By definition, `"molarity"="moles of solute"/"volume of solution"`...we require a mass of approx. `75*g`

Explanation:

Here you specify a `"molarity"=1.00*mol*L^-1` with respect to `Ni(NO_3)_2*6H_2O` and a volume of `250*mL-=0.250*L`...

And so we require a molar quantity of....

`"moles of solute"="molarity"xx"volume"`

And note that the given product has units of `mol*L^-1xxL-="moles"` as required....

And so .........

`"moles of nickel salt hydrate"=1.00*mol*L^-1xx0.250*L=0.250*mol`

And to get the mass we take the product....

`0.250*molxxunderbrace(290.79*g*mol^-1)_"molar mass of metal hydrate"=??*g`