# Question #be35b

Oct 16, 2016

$\sqrt{9} \sqrt{9} \sqrt{9} = 27$

#### Explanation:

Assuming the question is intended as $\sqrt{9} \sqrt{9} \sqrt{9}$, then we have

$\sqrt{9} \sqrt{9} \sqrt{9} = \sqrt{{3}^{2}} \sqrt{{3}^{2}} \sqrt{{3}^{2}}$

$= 3 \cdot 3 \cdot 3$

$= 27$