How many carbon atoms in a #3.25*"carat"# diamond?

1 Answer
Oct 16, 2016

Answer:

#"Number of carbon atoms"# #=# #0.054*molxx6.022xx10^23*mol^-1# #=# #??#

Explanation:

#"1 carat"# #=# #"200 mg"#

#"Number of moles"# #=# #"Mass"/"Molar mass"#

#"Number of moles of carbon"#

#=# #(3.25 cancel" carat"xx200xx10^-3*cancelg*cancel"carat"^-1)/(12.011*cancelg*mol^-1)#

#=# #0.054*mol#, and we mulitply this by #"Avogadro's number"# to get the number of carbon atoms.

#"Number of carbon atoms"# #=# #0.054*molxx6.022xx10^23*mol^-1# #=# #??#

And we go thru the same process for the aspirin sample:

#(0.75*g)/(180.16*g*mol^-1)xx6.022xx10^23*mol^-1# #=#

#"How many aspirin molecules?"#