Question #4f14c

1 Answer
Oct 17, 2016

Answer:

Molecular formula of Cadaverine is #C_5H_14N_2#

Explanation:

Given

Cadaverine contains 58.55% C, 13.81% H, and 27.40% N by mass, and has a molar mass of 102.2 g/mol.

Considering atomic masses as follows

#C->12" g/mol"#

#H->1" g/mol"#

#N->14" g/mol"#

Dividing the percentage of C,H and N by respective atomic mass and taking their ratio we get the ratio of number of atoms of C,H and N in the molecule of Cadaverine as follows

#n_C:n_H:n_N=58.55/12:13.81/1:27.40/14#
#=4.88:13.81:1.96#

#=4.88/1.96:13.81/1.96:1.96/1.96#

#~~2.5:7:1=5:14:2#

So empirical formula of Cadaverine is #C_5H_14N_2#

Let its molecular formula be #(C_5H_14N_2)_n#

By this formula its molar mass is #(5*12+14*1+2*14)n=102n" g/mol"#

Equating this with the given molar mass we get

#102n=102.2=>n~~1#

So molecular formula of Cadaverine is #C_5H_14N_2#