# Question 79ed9

Oct 18, 2016

The temperature change is $\text{107"^@"C}$.

#### Explanation:

Specific heat is the amount of heat necessary to increase the temperature of 1.00 gram of a substance by $\text{1.00"^@"C}$.

The equation to use in order to answer this question is:

$Q = m c \Delta T$, where $Q$ is energy, $m$ is mass, $c$ is specific heat, and $\Delta T$ is change in temperature.

Known
$m = \text{2.51 g}$
c=0.382 "J"/("g"^@"C")#
$Q = \text{102.53 J}$

Unknown
$\Delta T$

Solution
Rearrange the equation to isolate $\Delta T$.

$Q = m c \Delta T$

$\Delta T = \frac{Q}{m c}$

$\Delta T = \left(102.53 \cancel{\text{J")/(2.51cancel"g"*0.382 cancel"J"/(cancel"g"^@"C}}\right)$$=$$\text{107"^@"C}$