Question #79ed9

1 Answer
Oct 18, 2016

Answer:

The temperature change is #"107"^@"C"#.

Explanation:

Specific heat is the amount of heat necessary to increase the temperature of 1.00 gram of a substance by #"1.00"^@"C"#.

The equation to use in order to answer this question is:

#Q=mcDeltaT#, where #Q# is energy, #m# is mass, #c# is specific heat, and #DeltaT# is change in temperature.

Known
#m="2.51 g"#
#c=0.382 "J"/("g"^@"C")#
#Q="102.53 J"#

Unknown
#DeltaT#

Solution
Rearrange the equation to isolate #DeltaT#.

#Q=mcDeltaT#

#DeltaT=Q/(mc)#

#DeltaT=(102.53cancel"J")/(2.51cancel"g"*0.382 cancel"J"/(cancel"g"^@"C")##=##"107"^@"C"#