# Question 0d32e

Oct 18, 2016

In first oxide "Oxygen"->20% and "Metal"->80%

Here Ratio of

$\text{Oxygen":"Metal} = 1 : 4$

In 2nd oxide "Oxygen"->11.1% and "Metal"->88.9%#

Here Ratio of

$\text{Oxygen":"Metal} = 1 : 8$

So ratio of masses of metal combining with same mass of Oxygen in two oxides will be $= 4 : 8 = 1 : 2$ which is a ratio of simple whole number .So the law of multiple proportion is followed by the given data