Question

Question #471d2

Answer 1

That's obviously A.

Where the electric field is zero, the force on the charge is,

`vecF =qvecE = 0`

Explanation:

Consider the case of B.

Here, `E = 1/e` where `e` is the electronic charge.

Thus, magnitude of the force would be, `F = q/e` which is never zero, since the electronic charge is not zero.

If the charge is an electron (or a proton) then the absolute value of the force is 1.

Here, `e = 1.6 * 10^(-19) C`