Question #471d2

Question

1807 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-03-24T16:15:56

That's obviously A.

Where the electric field is zero, the force on the charge is,

$vecF =qvecE = 0$

Consider the case of B.

Here, $E = 1/e$ where $e$ is the electronic charge.

Thus, magnitude of the force would be, $F = q/e$ which is never zero, since the electronic charge is not zero.

If the charge is an electron (or a proton) then the absolute value of the force is 1.

Here, $e = 1.6 * 10^(-19) C$