# Question #471d2

Mar 24, 2017

That's obviously A.

Where the electric field is zero, the force on the charge is,

$\vec{F} = q \vec{E} = 0$

#### Explanation:

Consider the case of B.

Here, $E = \frac{1}{e}$ where $e$ is the electronic charge.

Thus, magnitude of the force would be, $F = \frac{q}{e}$ which is never zero, since the electronic charge is not zero.

If the charge is an electron (or a proton) then the absolute value of the force is 1.

Here, $e = 1.6 \cdot {10}^{- 19} C$