# Question #56b8e

${v}_{r m s} = \sqrt{\frac{3 R T}{M}}$
where $R = 8.31447 J m o {l}^{-} 1 {K}^{-} 1$
$M =$ the molar mass of the substance, expressed in kilograms
and $T$ is temperature of the sample in Kelvin.
${v}_{r m s} = \sqrt{\frac{3 \times 8.31447 \times 265}{32 \times {10}^{-} 3}}$
$= 454.5 m {s}^{-} 1$, rounded to one decimal place.