Question #bd799

1 Answer
Oct 27, 2016

#f(a+h) = 3(a+h)^2 + 2# or #f(a + h) = 3a^2 + 6ah + 3h^2 + 2#

Explanation:

To solve this problem you need to substitute #(a + h)# into the equation for everywhere in the equation there is an #x# or:

#f(a+h) = 3(a+h)^2 + 2#

If you want to expand this would equal:

#f(a + h) = 3(a + h)(a + h) + 2#

#f(a + h) = 3(a^2 + 2ah + h^2) +2#

#f(a + h) = 3a^2 + 6ah + 3h^2 + 2#