# Question #9a02f

##### 1 Answer

#### Answer:

Yes, you do.

#### Explanation:

The idea here is that you need to make sure that the four vials of stock solution have **enough** morphine sulfate to ensure the amount needed for your target solution.

Now, your solution is **for every**

This is equivalent to saying that

#3.0 color(red)(cancel(color(black)("g solute"))) * (10^3"mg")/(1color(red)(cancel(color(black)("g")))) = "3000 mg solute"#

The **total amount** of morphine sulfate present in the target solution will be

#250 color(red)(cancel(color(black)("mL solution"))) * "3000 mg solute"/(100color(red)(cancel(color(black)("mL solution")))) = "7500 mg solute"#

Now, **each vial** of stock solution will contain a **total amount** of

#50 color(red)(cancel(color(black)("mL solution"))) * "50 mg solute"/(1color(red)(cancel(color(black)("mL solution")))) = "2500 mg solute"#

This means that in order to get the total amount of morphine sulfate needed for your target solution, you must use

#7500 color(red)(cancel(color(black)("mg solute"))) * "1 vial stock"/(2500color(red)(cancel(color(black)("mg solute")))) = "3 vials stock"#

Therefore, you can say that you **do** have enough stock solution to prepare your target solution.

More specifically, you would mix **vials** of stock solution, the equivalent of **total volume** of the solution equal to