How many #cm^3# does one mole of Ideal gas occupy under standard conditions?

1 Answer
Nov 1, 2016

Answer:

You know that under standard conditions, #1# #mol# of Ideal Gas occupies a volume of #24.5*dm^3#, #24.5*L#

Explanation:

Note that here I use #1*atm# as the standard. New standards have been adopted.

But #1*cm^3=10^-3L#, i.e. #1*L=10^3cm^3#

And thus #24.5*L# #=# #24.5*cancelLxx10^3*cm^3*cancel(L^-1)# #=# #24.5xx10^3*cm^3# of dihydrogen gas.

What is the mass of this quantity?