# How many cm^3 does one mole of Ideal gas occupy under standard conditions?

Nov 1, 2016

You know that under standard conditions, $1$ $m o l$ of Ideal Gas occupies a volume of $24.5 \cdot {\mathrm{dm}}^{3}$, $24.5 \cdot L$

#### Explanation:

Note that here I use $1 \cdot a t m$ as the standard. New standards have been adopted.

But $1 \cdot c {m}^{3} = {10}^{-} 3 L$, i.e. $1 \cdot L = {10}^{3} c {m}^{3}$

And thus $24.5 \cdot L$ $=$ $24.5 \cdot \cancel{L} \times {10}^{3} \cdot c {m}^{3} \cdot \cancel{{L}^{-} 1}$ $=$ $24.5 \times {10}^{3} \cdot c {m}^{3}$ of dihydrogen gas.

What is the mass of this quantity?