Question

How many `cm^3` does one mole of Ideal gas occupy under standard conditions?

Answer 1

You know that under standard conditions, `1` `mol` of Ideal Gas occupies a volume of `24.5*dm^3`, `24.5*L`

Explanation:

Note that here I use `1*atm` as the standard. New standards have been adopted.

But `1*cm^3=10^-3L`, i.e. `1*L=10^3cm^3`

And thus `24.5*L` `=` `24.5*cancelLxx10^3*cm^3*cancel(L^-1)` `=` `24.5xx10^3*cm^3` of dihydrogen gas.

What is the mass of this quantity?