How do we represent the reduction of #MnO_2# by chloride anion to give #Mn^(2+)# and chlorine gas?

1 Answer
anor277
Oct 30, 2016

This is a redox reaction: manganese is reduced......

#MnO_2 +4H^+ + 2e^(-) rarr Mn^(2+) + 2H_2O# #(i)#

Explanation:

...........and chloride ion is oxidized.

#Cl^(-) rarr 1/2Cl_2(g) + e^-# #(ii)#

#(i) + (ii)xx2:# (we wish to remove electrons from the final redox equation.

#MnO_2 +4H^+ + 2Cl^(-) rarr Mn^(2+) + Cl_2(g) + 2H_2O#

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