Question #ff501

1 Answer
Nov 7, 2016

143.7

Explanation:

a) the first segment with r=3cm,
A_1=pir^2(39/360)=pi*3^2(39/360)=0.975pi

b) the three congruent circles with r=3.5cm,
A_2=3*pir^2=3*pi*3.5^2=36.75pi

c) the segment with r=3.2cm, (angle276^@)
A_3=pir^2(276/360)=pi*3.2^2*(276/360)=7.85pi

d) the small white circle with diameter =0.8, its radius r=0.8/2=0.4
A_4=pir^2=pi*(0.4)^2=0.16pi

Hence total coloured area A_C=A_1+A_2+A_3-A_4
=> A_C=0.975pi+36.75pi+7.85pi-0.16pi =(0.975+36.75+7.85-0.16)pi =45.415pi=142.68=142.7 (one decimal place)