Question #ff501

1 Answer
Nov 7, 2016

#143.7#

Explanation:

a) the first segment with #r=3cm#,
#A_1=pir^2(39/360)=pi*3^2(39/360)=0.975pi#

b) the three congruent circles with #r=3.5#cm,
#A_2=3*pir^2=3*pi*3.5^2=36.75pi#

c) the segment with #r=3.2#cm, (#angle276^@#)
#A_3=pir^2(276/360)=pi*3.2^2*(276/360)=7.85pi#

d) the small white circle with diameter #=0.8#, its radius #r=0.8/2=0.4#
#A_4=pir^2=pi*(0.4)^2=0.16pi#

Hence total coloured area #A_C=A_1+A_2+A_3-A_4#
#=> A_C=0.975pi+36.75pi+7.85pi-0.16pi =(0.975+36.75+7.85-0.16)pi =45.415pi=142.68=142.7# (one decimal place)