How much dihydrogen will be required to reduce completely a #1.22*mol# quantity of dinitrogen gas?

1 Answer
Nov 8, 2016

Answer:

#1/2N_2(g) + 3/2H_2(g) rarr NH_3(g)#

Explanation:

Given the stoichiometry, precisely #3.66*mol# dihydrogen gas are required to give ammonia. Each equiv dinitrogen requires three equiv dihydrogen. How much ammonia gas would be produced given complete reaction (an unlikely scenario)?