How much dihydrogen will be required to reduce completely a 1.22*mol quantity of dinitrogen gas?

1 Answer
anor277
Nov 8, 2016

1/2N_2(g) + 3/2H_2(g) rarr NH_3(g)

Explanation:

Given the stoichiometry, precisely 3.66*mol dihydrogen gas are required to give ammonia. Each equiv dinitrogen requires three equiv dihydrogen. How much ammonia gas would be produced given complete reaction (an unlikely scenario)?

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