# Question #d80bb

##### 1 Answer

Here's how you can do that.

#### Explanation:

The idea here is that you need to work with the solution's *percent concentration by mass*, *solute* you have in your sample.

So, the solution's percent concentration by mass is a measure of how many grams of **solute** you get in **solution**. Indirectly, this can help you figure out how many grams of *solvent* you have in

#color(purple)(bar(ul(|color(white)(a/a)color(black)(m_"solution" = m_"solute" + m_"solvent")color(white)(a/a)|)))#

In your case, a **for every**

#m_"solvent" = overbrace("100 g")^(color(blue)("mass of solution")) - overbrace("17.3 g")^(color(darkgreen)("mass of solute")) = "82.7 g solvent"#

Now all you have to do is scale up this proportion to figure out how many grams of **solution** would contain **solvent**

#355.2 color(red)(cancel(color(black)("g solvent"))) * "100 g solution"/(82.7 color(red)(cancel(color(black)("g solvent")))) = color(green)(bar(ul(|color(white)(a/a)color(black)("429.5 g solution")color(white)(a/a)|)))#

Therefore, the mass of **solute** must be

#m_"solute" = "429.5 g" - "355.2 g" = color(green)(bar(ul(|color(white)(a/a)color(black)("74.3 g solute")color(white)(a/a)|)))#