Drag the solute into the box that labels which solvent it will dissolve more easily within?

#" "" "" "color(white)(.)"CCl"_4" "" "" "" "" "" "" "" "" "" "" ""H"_2"O"#
#barul|stackrel(" ")(" "color(white)(stackrel(" ")("Place solute here"))" ")|" "" "" "" "barul|stackrel(" ")(" "color(white)(stackrel(" ")("Place solute here"))" ")|#

Sodium sulfide

1 Answer
Nov 10, 2016

The idea is that a solute that has intermolecular forces more similar to those in a solvent are more likely to mix well. Therefore:

  • Ionic compounds dissolve well in water, which can hydrogen-bond. Hydrogen-bonding interactions are generally close in strength to ion-pair interactions, which are present in ionic compounds.

Hence, it is a "good trade of energy" for ionic compounds to dissolve in water.

Think of it like trading things with someone else. You want a good deal when you trade, so you don't want to just hand over something valuable for something totally worthless in return.

  • Nonpolar compounds like hydrocarbons dissolve well in nonpolar solvents, for the same reasons as above; successful solvation is dependent on a "good trade of energy".

Here's a hint:


  • Sodium sulfide is ionic.
  • Hexane is nonpolar.
  • Iodine is nonpolar.
  • Formaldehyde is polar.


  • Water hydrogen-bonds.
  • Carbon tetrachloride is nonpolar.

Your final result should be an even distribution of answers; two on the left and two on the right.