#"2659 J"# of heat energy are required to heat a substance with a mass of #"24.25 g"# from #"23.7"^@"C"# to #"163.5"^@"C"#. What is its specific heat capacity?
2 Answers
The specific heat capacity is
Explanation:
So, the equation we are using is
=> Where
=> Where
=> Where
=> Where
#Q = mcDeltaT#
#Q = mc (T_2-T_1)#
#"2659 J" = "0.02425 kg"xxcxx"(163.5 - 23.7) °C"#
#"2659 J" = "0.02425 kg"xxcxx"139.8 °C"#
#c = "784.3 J/(°C·kg)"#
The specific heat capacity is
Hope this helps :)
The specific heat is
Explanation:
Apply the equation
Known
Unknown
Solution
Rearrange the equation