# #"2659 J"# of heat energy are required to heat a substance with a mass of #"24.25 g"# from #"23.7"^@"C"# to #"163.5"^@"C"#. What is its specific heat capacity?

##### 2 Answers

The specific heat capacity is

#### Explanation:

So, the equation we are using is

=> Where

=> Where

=> Where

=> Where

#Q = mcDeltaT#

#Q = mc (T_2-T_1)#

#"2659 J" = "0.02425 kg"xxcxx"(163.5 - 23.7) °C"#

#"2659 J" = "0.02425 kg"xxcxx"139.8 °C"#

#c = "784.3 J/(°C·kg)"#

The specific heat capacity is

Hope this helps :)

The specific heat is

#### Explanation:

Apply the equation

**Known**

**Unknown**

**Solution**

Rearrange the equation