A #33.25*mL# volume of nitric acid was required for equivalence with a #0.425*g# mass of sodium carbonate. What is the concentration of the nitric acid?
We work out the number of moles of each reagent...............and calculate
With all these problems, a stoichiometricall balanced equation that represents the reaction is a prerequisite.
And then we work out the number of moles of the reagents.
Given that 2 equiv of nitric acid are required to neutralize each equiv sodium carbonate, we can work out the concentration of the nitric acid as: