# How does energy evolve in the INCOMPLETE combustion of benzene...?

Nov 19, 2016

You might have to qualify your question here.

#### Explanation:

I can easily write a stoichiometric equation for the incomplete combustion of benzene:

${C}_{6} {H}_{6} \left(l\right) + 6 {O}_{2} \left(g\right) \rightarrow 4 C {O}_{2} \left(g\right) + C O \left(g\right) + C \left(s\right) + 3 {H}_{2} O \left(l\right)$

Is this balanced? Don't trust my arithmetic.

Of course, I don't know that this precise stoichiometry will occur, but given thermodynamic parameters (which you have ommitted!), we could work out the enthalpy change of the reaction.

The complete combustion of benzene occurs according to the stoichiometry...

${C}_{6} {H}_{6} \left(l\right) + \frac{15}{2} {O}_{2} \left(g\right) \rightarrow 6 C {O}_{2} \left(g\right) + 3 {H}_{2} O \left(l\right)$

And we would expect the thermal output of this reaction to be greater than that of the former. Why so?