Question #ce668

1 Answer
Nov 23, 2016

Answer:

#1.7 * 10^22 # molecules of #"H"_2"O"#

Explanation:

Given #"0.5 g"# of #"H"_2"O"# and using the molar mass of water

#M_( "H"_2"O") = "18.01528 g/mol"#

you have

#(0.5cancel("g"))/(18.01528cancel("g")"/mol") = "0.02775 moles"#

There are #6.022 xx 10^23# particles in a mole.

#(6.022 * 10^23"molecules H"_ 2"O")/(1cancel("mol")) * 0.02775cancel("moles") = 1.7 * 10^22"molecules H"_2"O"#