Question #44017

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Answer 1 · 2016-11-26T07:16:42

#f(x)=x^2+3x-1# and #g(x)=sinx#

Let #f(x)=x^2+3x-1#

and #g(x)=sinx#

Then,

#f(g(x))=f(sinx)=sin^2x+3sinx-1#

This is one solution.

Answer 2 · 2016-11-26T07:58:07

#f(x)=x^2+3x-1#
and #g(x)=sinx#

Given
#f(g(x))=sin^2x+3sinx-1#

If we put #sinx=g(x)# in RHS we get

#f(g(x))=(g(x))^2+3g(x)-1#

#=>f(x)=x^2+3x-1#

and #g(x)=sinx#