Question #46250

1 Answer
Nov 26, 2016

Answer:

Would you recheck your question? Given these conditions, #"concentration"=14.4*meq*L^-1#

Explanation:

First, we calculate #[Mg^(2+)]# in units of #mol*L^-1#.

#[Mg^(2+)]=(0.675*g)/(24.305*g*mol^-1)xx1/(1925xx10^-3*L)#

#=1.442xx10^-2*mol*L^-1#

#1.442xx10^-2*mol*L^-1xx1000*meq*mol^-1#

#=14.42*meq*L^-1#

#(i.e. "1 mole"=1000 xx10^-3)#

I am really not very happy in using this mass to represent a quantity of #Mg^(2+)#. It should have been a mass of a neutral salt, i.e. #MgCl_2# or #Mg(NO_3)_2#, which speciates in solution to #Mg^(2+)# etc. I would check your question.