If $541g$ of calcium is reacted with water to give a $1L$ volume of solution, what is $[Ca^(2+)]$ ?

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Answer 1 · 2016-11-26T01:38:21

$"Molarity"="Moles of solute"/"Volume of solution"$

And thus $"Molarity"=(541*cancelg)/(40.00*cancelg*mol^-1)xx1/(1*L)$ $>$ $10*mol*L^-1$ .

Dimensionally you get an answer in $1/(L*mol^-1)=mol*L^-1$ , because $1/(mol^-1)=1/(1/(mol))=mol$ , as required.

If 541*g541*g of calcium is reacted with water to give a 1*L1*L volume of solution, what is [Ca^(2+)][Ca^(2+)]?