Question

Question #fd3f5

Answer 1

`c=139/37`

Explanation:

I have interpreted this question as follows. Please contact me if my interpretation is incorrect.

`7/3=-10+3/(4-c)`

add 10 to both sides.

`7/3+10=cancel(-10)cancel(+10)+3/(4-c)`

`rArr7/3+30/3=3/(4-c)`

`rArrcolor(red)(37)/color(blue)(3)=color(blue)(3)/color(red)(4-c)`

`color(blue)"cross-multiplying"`

`rArrcolor(red)(37(4-c))=color(blue)(3)xxcolor(blue)(3)`

divide both sides by 37

`rArr4-c=9/37`

subtract 4 from both sides.

`cancel(4)cancel(-4)-c=9/37-4=9/37-148/37=-139/37`

`rArr-c=-139/37rArrc=139/37`