Question

Question #495a3

Answer 1

The answer is `=2cosx`

Explanation:

We use

`secx=1/cosx`

`cotx=cosx/sinx`

`sin2x=2sinxcosx`

Therefore,

`secx*cotx*sin2x`

`=1/cosx*cosx/sinx*2sinxcosx`

`=2cosx`