# What volume would a #10*g# mass of carbon monoxide enclosed in a piston occupy at #1*atm#, and #0# #""^@C#?

##### 2 Answers

Nov 29, 2016

#### Answer:

8.00 Liter

#### Explanation:

It can be further explained as :-

idle gas equation is

Here ,

P = 1 atm

V = To be find out

R = 0.08206 Universal Gas constant

T = 273 k

m = mass of gas [g], given 10 g

M = mass of 1 mole of gas [g] that is 28.01 of CO

By putting all values -

or

or

V = 8.00

Hence Answer is 8.00 Liter Volume