What volume would a #10*g# mass of carbon monoxide enclosed in a piston occupy at #1*atm#, and #0# #""^@C#?
So, we have
And thus if we assume carbon monoxide behaves ideally, its volume (if enclosed in a piston expanding against atmospheric pressure) would be approx.
It can be further explained as :-
idle gas equation is
P = 1 atm
V = To be find out
R = 0.08206 Universal Gas constant
T = 273 k
m = mass of gas [g], given 10 g
M = mass of 1 mole of gas [g] that is 28.01 of CO
By putting all values -
V = 8.00
Hence Answer is 8.00 Liter Volume