Question

Question #8e005

Answer 1

`2m^2n^2 sin^2 theta`, where `theta = angle` between `vecm and vec n`. If `vecm and vec n` are unit vectors, m and n are 1 and this becomes `2sin^2theta`

Explanation:

Assuming that the expression is

`|vecmXvecn|^2+|vecnXvecm|^2`, it is

`2m^2n^2 sin^2 theta`,

where `theta = angle` between `vecm and vec n`

`=2sin^2theta`, for unit vectors, having m and n as 1,

I have used

`vecmXvecn=-vecnXvecm` and

`vecm X vec n = mn sin theta vecz`,

where `vecz` is the unit vector in the direction of `vecm X vec n`.