Question #8e005

1 Answer
Jan 22, 2017

Answer:

#2m^2n^2 sin^2 theta#, where #theta = angle# between #vecm and vec n#. If #vecm and vec n# are unit vectors, m and n are 1 and this becomes #2sin^2theta#

Explanation:

Assuming that the expression is

#|vecmXvecn|^2+|vecnXvecm|^2#, it is

#2m^2n^2 sin^2 theta#,

where #theta = angle# between #vecm and vec n#

#=2sin^2theta#, for unit vectors, having m and n as 1,

I have used

#vecmXvecn=-vecnXvecm# and

#vecm X vec n = mn sin theta vecz#,

where #vecz# is the unit vector in the direction of #vecm X vec n#.