# Question #5e1fc

Nov 29, 2016

$x = 0$

#### Explanation:

${\left(2 x + 3\right)}^{3} = 27 = {3}^{3}$ so

if ${a}^{n} = {b}^{n}$ then for $n$ odd there is a real root such that

$a = b$ or in our case

$2 x + 3 = 3$ so $x = 0$