Question #6e801

1 Answer
Dec 1, 2016

Answer:

Here's what I got.

Explanation:

Assuming that your solution contains #"1 g"# of solute in #"100 mL"# of solution, you can say that it has a #1%# mass by volume percent concentration, i.e. #"1% m/v"#.

A solution's mass by volume percent concentration is calculated by looking at how many grams of solute you get for every #"100 mL"# of solution.

In this case, you know that #"100 mL"# of solution contains #"1 g"# of solute, so its mass by volume percent concentration will be #"1% m/v"#.

How about a solution that contains #"1 g"# of solute in #"50 mL"# of solution, what would its mass by volume percent concentration be?

#100 color(red)(cancel(color(black)("mL solution"))) * overbrace("1 g solute"/(50color(red)(cancel(color(black)("mL solution")))))^(color(blue)("known composition")) = "2 g solute"#

This means that the solution is #"2% m/v"#, since it contains #"2 g"# of solute for every #"100 mL"# of solution.