# Question 6e801

Dec 1, 2016

Here's what I got.

#### Explanation:

Assuming that your solution contains $\text{1 g}$ of solute in $\text{100 mL}$ of solution, you can say that it has a 1% mass by volume percent concentration, i.e. $\text{1% m/v}$.

A solution's mass by volume percent concentration is calculated by looking at how many grams of solute you get for every $\text{100 mL}$ of solution.

In this case, you know that $\text{100 mL}$ of solution contains $\text{1 g}$ of solute, so its mass by volume percent concentration will be $\text{1% m/v}$.

How about a solution that contains $\text{1 g}$ of solute in $\text{50 mL}$ of solution, what would its mass by volume percent concentration be?

100 color(red)(cancel(color(black)("mL solution"))) * overbrace("1 g solute"/(50color(red)(cancel(color(black)("mL solution")))))^(color(blue)("known composition")) = "2 g solute"#

This means that the solution is $\text{2% m/v}$, since it contains $\text{2 g}$ of solute for every $\text{100 mL}$ of solution.